Then we set $Q = 48$kHz so that $P = 48000 / S$, or $P = C_V F_A
/ F_V$.
+Note that the original sampling rate of the audio content is
+irrelevant. Also, skipping or doubling of video frames is analagous
+to audio resampling: the data are the same, just represented with more
+or fewer samples.
+
+
+\section{Further thoughts}
+
+Consider the case where the content video rate $C_V = 24$ and the DCP
+video rate $F_V = 25$. Then 46080 (resampled) samples of audio
+content last 1s at the original rate or $24/25$s at the DCP rate and
+1s of DCP is made up of 48000 (resampled) content samples.
+
\end{document}